Merge K Sorted Arrays and Print Sorted Output

Reverse Array
Pair Sum Equals Number
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Largest Sum Subarray
Missing Number
Odd Occuring Number
Sort by Frequency
First and Second Smallest
Majority Element
Difference between elements
Arrange Even and Odd
Closest Sum Elements
Distinct Elements
First Repeating Number
Common Elements in Arrays
Smallest Missing Number
Max Adjacent Sum
Find Occurrences of Number
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Pair with given difference
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Replace Elements
First Repeating Element
Move Zeroes to End
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Maximum Average Subarray
Subarray Sum Equal to X
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Largest Pair Sum
Segregate 0s 1s and 2s
Find Duplicates
Consecutive Elements Check
Triplet with given Sum
Binary Search in Sorted Array
Fixed point in sorted array
Reorder Elements by Indexes
Merging two sorted arrays
Find next greater number
Reorder array using given indexes
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Merge two sorted arrays
Subarray and Subsequence
Rearrange array maximum minimum form
Find the lost element from a duplicated array
Count minimum steps to get the given array
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Minimum number of jumps to reach the end of an array
Subarray with given sum
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Smallest positive number missing unsorted array
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Find pair with given difference
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Maximum circular subarray sum
Count possible triangles
Longest Increasing Subsequence
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Maximum Repeating Number
Positive Negative Arrangement
Find a Peak element
Elements More Than n/k
Max Product Subsequence
Longest Bitonic subarray in an array
Number of smaller elements on right side
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Maximum sum increasing subsequence
Find the two numbers with odd occurrences in an unsorted array
Largest subarray with equal number of 0's and 1's
Maximum product subarray
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Find the row with maximum number of 1's
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Merge k Sorted Arrays
Flip Zeroes for Consecutive 1's
Least Average Subarray
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Number of strictly increasing subarrays
Minimum difference between any two elements in an array
Number of pairs with given sum
Make Array Palindrome
Dynamic Programming, Longest Bitonic SubSequence

Given k sorted arrays of size n each, write a program to merge those arrays and prints the sorted output


arr[][] = {{1,5,7},{2,4,6},{3,10,13}}


Time Complexity : O(nklogk)

where k is the number of sorted arrays and n is the size of the array
In this method the main idea is using minheap


1. Create an output array of size n*k

2. Create a min heap of size k and insert first element in all the arrays into the min heap

3. Initialize count = 0 and till count less than n*k.

  1. Get the minimum element from heap(ie, root) and store it in output array ie,output[count]
  2. Replace heap root with next element from the array from which the element is extracted. If the array doesn’t have any more elements, then replace root with infinite. After replacing the root, heapify the tree.

4. Print the output array.

C++ Program

#define n 3
using namespace std;

// A min heap node
struct MinHeapNode
    int element; // The element to be stored
    int i; // index of the array from which the element is taken
    int j; // index of the next element to be picked from array
// Prototype of a utility function to swap two min heap nodes
void swap(MinHeapNode *x, MinHeapNode *y);
// A class for Min Heap
class MinHeap
    MinHeapNode *harr; // pointer to array of elements in heap
    int heap_size; // size of min heap
    // Constructor: creates a min heap of given size
    MinHeap(MinHeapNode a[], int size);
    // to heapify a subtree with root at given index
    void MinHeapify(int );
    // to get index of left child of node at index i
    int left(int i) { return (2*i + 1); }
    // to get index of right child of node at index i
    int right(int i) { return (2*i + 2); }
    // to get the root
    MinHeapNode getMin() { return harr[0]; }
    // to replace root with new node x and heapify() new root
    void replaceMin(MinHeapNode x) { harr[0] = x;  MinHeapify(0); }
// This function takes an array of arrays as an argument and
// All arrays are assumed to be sorted. It merges them together
// and prints the final sorted output.
int *mergeKSortedArrays(int arr[][n], int k)
    int *output = new int[n*k];  // To store output array
    // Create a min heap with k heap nodes.  Every heap node
    // has first element of an array
    MinHeapNode *harr = new MinHeapNode[k];
    for (int i = 0; i < k; i++)
        harr[i].element = arr[i][0]; // Store the first element
        harr[i].i = i;  // index of array
        harr[i].j = 1;  // Index of next element to be stored from array
    MinHeap hp(harr, k); // Create the heap
    // Now one by one get the minimum element from min
    // heap and replace it with next element of its array
    for (int count = 0; count < n*k; count++)
        // Get the minimum element and store it in output
        MinHeapNode root = hp.getMin();
        output[count] = root.element;
        // Find the next element that will replace current
        // root of heap. The next element belongs to same
        // array as the current root.
        if (root.j < n)
            root.element = arr[root.i][root.j];
            root.j += 1;
        // If root was the last element of its array
        else root.element =  INT_MAX; //INT_MAX is for infinite
        // Replace root with next element of array
    return output;
// Standard Min Heap Methods
    // Constructor: Builds a heap from a given array a[] of given size
MinHeap::MinHeap(MinHeapNode a[], int size)
    heap_size = size;
    harr = a;  // store address of array
    int i = (heap_size - 1)/2;
    while (i >= 0)
// A recursive method to heapify a subtree with root at given index
// This method assumes that the subtrees are already heapified
void MinHeap::MinHeapify(int i)
    int l = left(i);
    int r = right(i);
    int smallest = i;
    if (l < heap_size && harr[l].element < harr[i].element)
        smallest = l;
    if (r < heap_size && harr[r].element < harr[smallest].element)
        smallest = r;
    if (smallest != i)
        swap(&harr[i], &harr[smallest]);
// A utility function to swap two elements
void swap(MinHeapNode *x, MinHeapNode *y)
    MinHeapNode temp = *x;  *x = *y;  *y = temp;
// A utility function to print array elements
void printArray(int arr[], int size)
   for (int i=0; i < size; i++)
       cout << arr[i] << " ";

int main()
    // Change n at the top to change number of elements
    // in an array
    int arr[][n] = {{1,5,7},{2,4,6},{3,10,13}} ;
    int k = sizeof(arr)/sizeof(arr[0]);
    int *output = mergeKSortedArrays(arr, k);
    cout << "Merged array is " << endl;
    printArray(output, n*k);
    return 0;
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